Thursday, May 10, 2018

What is a number whose cube is equal to the number itself but its square is not equal to the number itself


It is always good if you solve first by your own.


Subtract x2x2 from both sides to get:



Now, we know that x2x2 is not equal to xx, which means x2−xx2−x is not equal to zero. So, it’s safe to divide both sides by x2−xx2−x :


So, the answer is -1.

Here, it was a key that since x and x square are not equal, x square - x can be cut from both sides of the equation. This results in x as minus 1 as the answer.

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